Chemistry · 4. Acids, bases and salts
pH, neutralisation and acid–base titration
Determine an unknown concentration from reaction stoichiometry and the equivalence point.
Driving question
How accurately can a colour change reveal an unknown concentration?
Curriculum coverage
Vietnam 2018 and Cambridge: pH, neutralisation, concentration and titration.
Model scope and limitations
pH values are educational estimates; temperature, ionic activity and weak species can shift equivalence away from pH 7.
Learning objectives
- Distinguish equivalence point from indicator end point.
- Calculate amount using n = C·V with V in litres.
- Choose a suitable indicator and read a burette correctly.
Prerequisite knowledge
- Moles, molar concentration and balanced equations
- Meaning of pH
Core knowledge
Stoichiometry at equivalence
Acid and base amounts follow equation coefficients; the ratio is not always 1:1.
Volume conversion
In n = C·V, convert mL to L by dividing by 1000.
End point
The indicator changes near equivalence; choose its transition range within the steep pH change.
Worked example
25.00 mL HCl requires 20.00 mL of 0.1000 mol/L NaOH. For 1:1 stoichiometry, C(HCl) = 0.1000×20.00/25.00 = 0.08000 mol/L.
Misconceptions to avoid
- Equivalence is stoichiometric; its pH is not always 7.
- An indicator end point only approximates equivalence and can introduce indicator error.
Virtual experiment procedure: Acid–base titration
- Rinse the burette with titrant and record the initial reading at eye level.
- Add titrant quickly at first, then dropwise near the end point.
- Repeat until at least two concordant titres are obtained.
Safety and cautions
- Acids and bases may be corrosive; wear eye protection and rinse splashes immediately.
- Never pipette by mouth.
Evidence to collect
- Initial/final burette readings, titres and concordant values.
- A concentration calculation using the balanced equation and mean concordant titre.
Diagnostic check
1. In n = C·V, if C is in mol/L, which unit must V use?
Show answer and explanation
Correct answer: Litres
Convert mL to L before multiplying by molar concentration.
2. What defines the equivalence point in a titration?
Show answer and explanation
Correct answer: Stoichiometrically equivalent amounts
Equivalence is defined by stoichiometry; its pH depends on the acid–base system.
3. How should uncertainty near the end point be reduced?
Show answer and explanation
Correct answer: Add dropwise and swirl
Dropwise addition, swirling and eye-level reading reduce overshoot and parallax.
Application practice
1. How many moles are in 25.0 mL of 0.100 mol/L NaOH?
Show answer and explanation
Correct answer: 2.50×10⁻³ mol
n = 0.100 × 0.0250 = 2.50×10⁻³ mol.
2. H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O. How much NaOH reacts with 0.010 mol H₂SO₄?
Show answer and explanation
Correct answer: 0.020 mol
The coefficient ratio NaOH:H₂SO₄ is 2:1.
3. Why should equivalence pH not always be assumed to be 7?
Show answer and explanation
Correct answer: Weak acids or bases create hydrolysis equilibria
Salts of weak acids/bases can hydrolyse, shifting equivalence pH from 7.
Academic references
- OpenStax Chemistry 2e — peer-reviewed general chemistry
- IUPAC Gold Book — authoritative chemical terminology
- BIPM — SI Brochure, 9th edition
This lesson is maintained against the cited sources below. Simulations are learning models and do not replace supervised physical-laboratory safety procedures.
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