Biology · 2. Membranes and transport
Diffusion, osmosis and active transport
Predict transport direction from gradients and test it using percentage mass change.
Driving question
What determines the direction in which water or solute crosses a membrane?
Curriculum coverage
Vietnam Biology 10; Cambridge IGCSE/AS membrane transport.
Model scope and limitations
Osmosis is net water movement through a selectively permeable membrane; in living tissue, wall pressure also affects equilibrium.
Learning objectives
- Explain diffusion and osmosis using particle motion.
- Calculate percentage mass change.
- Estimate the isotonic point from a graph.
Prerequisite knowledge
- Concentration, percentages and membrane structure.
Core knowledge
Diffusion
Particles move randomly, with net movement from higher to lower concentration.
Osmosis
Water moves net from higher to lower water potential through a selectively permeable membrane.
Active transport
Membrane proteins use energy to move substances against an electrochemical gradient.
Worked example
A potato cylinder rises from 2.50 g to 2.75 g: % change = (2.75 − 2.50)/2.50 × 100 = +10%.
Misconceptions to avoid
- Water still moves both ways at equilibrium; only net movement is zero.
- In plasmolysis the membrane pulls from the wall; the wall itself does not shrink.
Virtual experiment procedure: Osmosis and plasmolysis
- Cut equal tissue cylinders, blot consistently and record initial mass.
- Immerse for equal times across concentrations, controlling temperature and volume.
- Calculate % change, plot against concentration and interpolate the 0% crossing.
Safety and cautions
- Use cutting tools on a board away from fingers; never taste solutions.
Evidence to collect
- Initial/final mass table, percentage changes, graph and isotonic estimate.
Diagnostic check
1. Which way does water move net?
Show answer and explanation
Correct answer: Lower water potential
Net water movement is from higher to lower water potential.
2. Why use percentage rather than raw mass change?
Show answer and explanation
Correct answer: Compare different starting masses
Normalising to starting mass makes comparisons fair.
Application practice
1. A sample falls from 4.0 g to 3.6 g. Percentage change?
Show answer and explanation
Correct answer: −10%
(3.6 − 4.0)/4.0 × 100 = −10%.
2. A plant cell in a hypertonic solution will?
Show answer and explanation
Correct answer: Lose water and may plasmolyse
The external solution has lower water potential, so water leaves.
3. The graph point at 0% mass change estimates what?
Show answer and explanation
Correct answer: Isotonic point
No mass change suggests no appreciable net water movement.
Academic references
This lesson is maintained against the cited sources below. Simulations are learning models and do not replace supervised physical-laboratory safety procedures.
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