Physics · 7. Waves and sound
Travelling waves, sound and standing waves
Connect frequency, wavelength and speed; explain reflection, resonance and harmonics with wave models.
Driving question
Why does a string resonate strongly only at particular frequencies?
Curriculum coverage
Vietnam Physics 11–12; Cambridge IGCSE 0625 and AS & A Level 9702: properties of waves, sound and stationary waves.
Model scope and limitations
The string model assumes a uniform string, small oscillations, fixed ends and negligible damping. For sound in air, speed depends on the medium and temperature, not on source frequency.
Learning objectives
- Use v = fλ and distinguish source-controlled from medium-controlled quantities.
- Identify transverse and longitudinal waves, nodes and antinodes.
- Derive the natural frequencies of a string fixed at both ends.
Prerequisite knowledge
- Period T = 1/f and unit conversion.
- Tension, mass and square roots.
Core knowledge
Wave equation
A periodic wave obeys v = fλ. Across a boundary, source frequency stays constant while v and λ may change.
Standing wave
Two equal-frequency, equal-amplitude waves travelling oppositely superpose to form zero-amplitude nodes and maximum-amplitude antinodes.
String fixed at both ends
The condition L = nλ/2 gives fₙ = nv/(2L), n = 1, 2, 3, …; adjacent nodes are λ/2 apart.
Worked example
For a 0.80 m string with linear density μ = 5.00×10⁻³ kg/m and tension 80.0 N, v = √(F/μ) ≈ 126 m/s. The fundamental is f₁ = v/(2L) ≈ 79.1 Hz and the third harmonic is about 237 Hz.
Misconceptions to avoid
- Greater amplitude does not make a wave travel faster in the linear model of the same medium.
- Nodes and antinodes are fixed features of the pattern; medium particles still oscillate away from nodes.
- A wave transfers energy without transporting the medium bodily over long distances.
Virtual experiment procedure: Standing waves on a string
- Choose string length and tension, then predict the fundamental before running.
- Sweep frequency slowly and record values producing 1, 2 and 3 clear antinodes.
- Test fₙ/f₁ ≈ n and measure adjacent-node spacing to infer λ.
Safety and cautions
- In a real experiment, secure the string and masses and stay out of the path of a string that could snap.
Evidence to collect
- A table of antinode count n, frequency fₙ, inferred wavelength and ratio fₙ/f₁.
- A conclusion linking tension, speed and resonant frequency, with a model limitation.
Diagnostic check
1. Which quantity is set by the oscillator when a wave crosses into another medium?
Show answer and explanation
Correct answer: Frequency
Frequency remains continuous across the boundary; speed and wavelength adjust to the medium.
2. The distance between adjacent nodes is?
Show answer and explanation
Correct answer: λ/2
Adjacent nodes are separated by half a wavelength.
3. What is the unit of frequency?
Show answer and explanation
Correct answer: Hz = s⁻¹
Frequency is the number of cycles per second.
Application practice
1. A wave has f = 200 Hz and λ = 1.70 m. What is its speed?
Show answer and explanation
Correct answer: 340 m/s
v = fλ = 200×1.70 = 340 m/s.
2. A 0.60 m string fixed at both ends has wave speed 120 m/s. What is f₁?
Show answer and explanation
Correct answer: 100 Hz
f₁ = v/(2L) = 120/1.20 = 100 Hz.
3. If string tension is quadrupled while μ and L stay fixed, how does f₁ change?
Show answer and explanation
Correct answer: It doubles
Since v = √(F/μ), quadrupling F doubles v and every natural frequency.
Academic references
- Cambridge IGCSE Physics 0625 — official syllabus and resources
- Cambridge AS & A Level Physics 9702 — official syllabus
- OpenStax Physics — peer-reviewed high-school physics
- BIPM — SI Brochure, 9th edition
This lesson is maintained against the cited sources below. Simulations are learning models and do not replace supervised physical-laboratory safety procedures.
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